A mass m is revolving in a vertical circle at the end of a string of length 20 cm. By how much times does the tension of the string at the lowest point exceed the tension at the topmost point –
Text Solution
Verified by ExpertsThe correct answer is:
C
T 1 – mg = 
......(i)
T 2 + mg = 
......(ii)
and 0 + 
mu 2 = mg 2 λ + 
mv 2
(i-ii) T 1 – T 2 = 
(u 2 – v 2 ) + 2mg
= 
(4 g λ ) + 2 mg
T 1 – T 2 = 6 mg.
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